(-4x^2)/(4x+8)^2+(2x)/(4x+8)=0

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Solution for (-4x^2)/(4x+8)^2+(2x)/(4x+8)=0 equation: 



(-4x^2)/(4x+8)^2+(2x)/(4x+8)=0



Domain of the equation: (4x+8)^2!=0

x∈R





Domain of the equation: (4x+8)!=0

We move all terms containing x to the left, all other terms to the right

4x!=-8

x!=-8/4

x!=-2

x∈R



We calculate fractions


((-4x^2)*(4x+8))/((4x+8)^2*(4x+8))+(2x*(4x+8)^2)/((4x+8)^2*(4x+8))=0



We calculate terms in parentheses: +((-4x^2)*(4x+8))/((4x+8)^2*(4x+8)), so:

(-4x^2)*(4x+8))/((4x+8)^2*(4x+8)

We multiply all the terms by the denominator


(-4x^2)*(4x+8))

Back to the equation:

+((-4x^2)*(4x+8)))





We calculate terms in parentheses: +(2x*(4x+8)^2)/((4x+8)^2*(4x+8)), so:

2x*(4x+8)^2)/((4x+8)^2*(4x+8)

We multiply all the terms by the denominator


2x*(4x+8)^2)

We multiply parentheses

8x^2+16x^2

We add all the numbers together, and all the variables

24x^2

Back to the equation:

+(24x^2)

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